Url Xslt — Chrome Unsafe Attempt To Load

<?xml version="1.0"?> <?xml-stylesheet type="text/xsl" href="data:text/xsl,<xsl:stylesheet%20version='1.0'%20xmlns:xsl='http://www.w3.org/1999/XSL/Transform'><xsl:template%20match='/'>...</xsl:template></xsl:stylesheet>"?> File structure:

<?xml version="1.0"?> <?xml-stylesheet type="text/xsl" href="style.xslt"?> <!-- or subfolder --> <?xml-stylesheet type="text/xsl" href="xslt/style.xslt"?> Instead of opening files directly ( file:// ), serve them via http://localhost .

# Python 3 python -m http.server 8000 python -m SimpleHTTPServer 8000 chrome unsafe attempt to load url xslt

app.use((req, res, next) => res.header("Access-Control-Allow-Origin", "*"); next(); ); Embed the XSLT as a data URI:

cd project python -m http.server 8000 # Open http://localhost:8000/data.xml | Fix | Best for | Difficulty | |-----|----------|------------| | Relative paths | Same folder structure | Easy | | Local web server | Development/testing | Medium | | Disable web security | Quick local test only | Easy (risky) | | CORS headers | Production servers | Medium | | Data URI | Very small XSLT | Hard | npx http-server -p 8000 ⚠️ Only use this

Then open http://localhost:8000/data.xml

The root cause is Chrome's security policy. The cleanest solution is to use a local web server instead of opening XML files directly from disk. ?xml-stylesheet type="text/xsl" href="data:text/xsl

npx http-server -p 8000 ⚠️ Only use this for local testing – do not browse normally with this flag.