Class 9 Higher Math Solution Bd Apr 2026

sinθ = opposite/hyp = 3k/5k = 3/5 cosθ = adjacent/hyp = 4k/5k = 4/5 5.1 Quadratic Formula For ax² + bx + c = 0 (a≠0): x = [-b ± √(b² - 4ac)] / (2a)

Solution: Let opposite=3k, adjacent=4k Hypotenuse = √[(3k)² + (4k)²] = √(9k²+16k²) = 5k Class 9 Higher Math Solution Bd

Solution: 3x - 7 > 2x + 5 → 3x - 2x > 5 + 7 → x > 12 sinθ = opposite/hyp = 3k/5k = 3/5 cosθ